Distance from Savage to Bad Liebenwerda
The shortest distance (air line) between Savage and Bad Liebenwerda is 4,486.40 mi (7,220.16 km).
How far is Savage from Bad Liebenwerda
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 03:45 (12.08.2025)
Bad Liebenwerda is located in Elbe-Elster, Germany within 51° 31' 0.12" N 13° 24' 0" E (51.5167, 13.4000) coordinates. The local time in Bad Liebenwerda is 10:45 (12.08.2025)
The calculated flying distance from Bad Liebenwerda to Bad Liebenwerda is 4,486.40 miles which is equal to 7,220.16 km.
Savage, Minnesota, United States
Related Distances from Savage
Bad Liebenwerda, Elbe-Elster, Germany