Distance from Savage to Argenteuil
The shortest distance (air line) between Savage and Argenteuil is 4,212.24 mi (6,778.95 km).
How far is Savage from Argenteuil
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 05:18 (05.08.2025)
Argenteuil is located in Val-d’Oise, France within 48° 57' 0" N 2° 15' 0" E (48.9500, 2.2500) coordinates. The local time in Argenteuil is 12:18 (05.08.2025)
The calculated flying distance from Argenteuil to Argenteuil is 4,212.24 miles which is equal to 6,778.95 km.
Savage, Minnesota, United States
Related Distances from Savage
Argenteuil, Val-d’Oise, France