Distance from Savage to Aleksandrovac
The shortest distance (air line) between Savage and Aleksandrovac is 5,131.25 mi (8,257.95 km).
How far is Savage from Aleksandrovac
Savage is located in Minnesota, United States within 44° 45' 16.2" N -94° 38' 12.48" W (44.7545, -93.3632) coordinates. The local time in Savage is 15:03 (14.11.2025)
Aleksandrovac is located in Rasinska oblast, Serbia within 43° 27' 19.08" N 21° 3' 5.04" E (43.4553, 21.0514) coordinates. The local time in Aleksandrovac is 22:03 (14.11.2025)
The calculated flying distance from Aleksandrovac to Aleksandrovac is 5,131.25 miles which is equal to 8,257.95 km.
Savage, Minnesota, United States
Related Distances from Savage
Aleksandrovac, Rasinska oblast, Serbia