Distance from Sauk Rapids to Aleksandrow Lodzki
The shortest distance (air line) between Sauk Rapids and Aleksandrow Lodzki is 4,634.82 mi (7,459.02 km).
How far is Sauk Rapids from Aleksandrow Lodzki
Sauk Rapids is located in Minnesota, United States within 45° 35' 53.16" N -95° 50' 46.32" W (45.5981, -94.1538) coordinates. The local time in Sauk Rapids is 11:52 (11.11.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 18:52 (11.11.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 4,634.82 miles which is equal to 7,459.02 km.
Sauk Rapids, Minnesota, United States
Related Distances from Sauk Rapids
Aleksandrow Lodzki, Łódzki, Poland