Distance from Sauk Rapids to Aleksandrow Kujawski
The shortest distance (air line) between Sauk Rapids and Aleksandrow Kujawski is 4,564.67 mi (7,346.13 km).
How far is Sauk Rapids from Aleksandrow Kujawski
Sauk Rapids is located in Minnesota, United States within 45° 35' 53.16" N -95° 50' 46.32" W (45.5981, -94.1538) coordinates. The local time in Sauk Rapids is 11:09 (11.11.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 18:09 (11.11.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,564.67 miles which is equal to 7,346.13 km.
Sauk Rapids, Minnesota, United States
Related Distances from Sauk Rapids
Aleksandrow Kujawski, Włocławski, Poland