Distance from Sapulpa to Sveti Ivan Zelina
The shortest distance (air line) between Sapulpa and Sveti Ivan Zelina is 5,385.50 mi (8,667.12 km).
How far is Sapulpa from Sveti Ivan Zelina
Sapulpa is located in Oklahoma, United States within 36° 0' 32.76" N -97° 53' 58.92" W (36.0091, -96.1003) coordinates. The local time in Sapulpa is 19:33 (05.08.2025)
Sveti Ivan Zelina is located in Zagrebačka županija, Croatia within 45° 57' 34.56" N 16° 14' 35.16" E (45.9596, 16.2431) coordinates. The local time in Sveti Ivan Zelina is 02:33 (06.08.2025)
The calculated flying distance from Sveti Ivan Zelina to Sveti Ivan Zelina is 5,385.50 miles which is equal to 8,667.12 km.
Sapulpa, Oklahoma, United States
Related Distances from Sapulpa
Sveti Ivan Zelina, Zagrebačka županija, Croatia