Distance from Sapulpa to Novy Jicin
The shortest distance (air line) between Sapulpa and Novy Jicin is 5,285.46 mi (8,506.12 km).
How far is Sapulpa from Novy Jicin
Sapulpa is located in Oklahoma, United States within 36° 0' 32.76" N -97° 53' 58.92" W (36.0091, -96.1003) coordinates. The local time in Sapulpa is 05:43 (07.08.2025)
Novy Jicin is located in Moravskoslezský kraj, Czechia within 49° 35' 39.84" N 18° 0' 37.08" E (49.5944, 18.0103) coordinates. The local time in Novy Jicin is 12:43 (07.08.2025)
The calculated flying distance from Novy Jicin to Novy Jicin is 5,285.46 miles which is equal to 8,506.12 km.
Sapulpa, Oklahoma, United States
Related Distances from Sapulpa
Novy Jicin, Moravskoslezský kraj, Czechia