Distance from Sandridge to Alexandroupoli
The shortest distance (air line) between Sandridge and Alexandroupoli is 1,447.62 mi (2,329.72 km).
How far is Sandridge from Alexandroupoli
Sandridge is located in Hertfordshire, United Kingdom within 51° 46' 50.88" N -1° 41' 46.32" W (51.7808, -0.3038) coordinates. The local time in Sandridge is 00:35 (13.08.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 02:35 (13.08.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 1,447.62 miles which is equal to 2,329.72 km.
Sandridge, Hertfordshire, United Kingdom