Distance from San Martino Buon Albergo to Waukegan
The shortest distance (air line) between San Martino Buon Albergo and Waukegan is 4,593.16 mi (7,391.97 km).
How far is San Martino Buon Albergo from Waukegan
San Martino Buon Albergo is located in Verona, Italy within 45° 25' 0.12" N 11° 5' 60" E (45.4167, 11.1000) coordinates. The local time in San Martino Buon Albergo is 05:48 (28.08.2025)
Waukegan is located in Illinois, United States within 42° 22' 11.28" N -88° 7' 42.24" W (42.3698, -87.8716) coordinates. The local time in Waukegan is 22:48 (27.08.2025)
The calculated flying distance from Waukegan to Waukegan is 4,593.16 miles which is equal to 7,391.97 km.
San Martino Buon Albergo, Verona, Italy
Related Distances from San Martino Buon Albergo
Waukegan, Illinois, United States