Distance from San Martino Buon Albergo to Austintown
The shortest distance (air line) between San Martino Buon Albergo and Austintown is 4,365.49 mi (7,025.58 km).
How far is San Martino Buon Albergo from Austintown
San Martino Buon Albergo is located in Verona, Italy within 45° 25' 0.12" N 11° 5' 60" E (45.4167, 11.1000) coordinates. The local time in San Martino Buon Albergo is 18:53 (12.08.2025)
Austintown is located in Ohio, United States within 41° 5' 35.52" N -81° 15' 34.2" W (41.0932, -80.7405) coordinates. The local time in Austintown is 12:53 (12.08.2025)
The calculated flying distance from Austintown to Austintown is 4,365.49 miles which is equal to 7,025.58 km.
San Martino Buon Albergo, Verona, Italy
Related Distances from San Martino Buon Albergo
Austintown, Ohio, United States