Distance from San Giuseppe Vesuviano to Six-Fours-les-Plages
The shortest distance (air line) between San Giuseppe Vesuviano and Six-Fours-les-Plages is 472.37 mi (760.20 km).
How far is San Giuseppe Vesuviano from Six-Fours-les-Plages
San Giuseppe Vesuviano is located in Napoli, Italy within 40° 49' 59.88" N 14° 30' 0" E (40.8333, 14.5000) coordinates. The local time in San Giuseppe Vesuviano is 22:26 (30.10.2025)
Six-Fours-les-Plages is located in Var, France within 43° 6' 3.24" N 5° 49' 12" E (43.1009, 5.8200) coordinates. The local time in Six-Fours-les-Plages is 22:26 (30.10.2025)
The calculated flying distance from Six-Fours-les-Plages to Six-Fours-les-Plages is 472.37 miles which is equal to 760.20 km.
San Giuseppe Vesuviano, Napoli, Italy
Related Distances from San Giuseppe Vesuviano
Six-Fours-les-Plages, Var, France