Distance from San Giuseppe Vesuviano to Civita Castellana
The shortest distance (air line) between San Giuseppe Vesuviano and Civita Castellana is 147.94 mi (238.09 km).
How far is San Giuseppe Vesuviano from Civita Castellana
San Giuseppe Vesuviano is located in Napoli, Italy within 40° 49' 59.88" N 14° 30' 0" E (40.8333, 14.5000) coordinates. The local time in San Giuseppe Vesuviano is 00:25 (12.11.2025)
Civita Castellana is located in Viterbo, Italy within 42° 17' 45.96" N 12° 24' 36" E (42.2961, 12.4100) coordinates. The local time in Civita Castellana is 00:25 (12.11.2025)
The calculated flying distance from Civita Castellana to Civita Castellana is 147.94 miles which is equal to 238.09 km.
San Giuseppe Vesuviano, Napoli, Italy
Related Distances from San Giuseppe Vesuviano
Civita Castellana, Viterbo, Italy