Distance from San Giuseppe Vesuviano to Alexandroupoli
The shortest distance (air line) between San Giuseppe Vesuviano and Alexandroupoli is 593.73 mi (955.51 km).
How far is San Giuseppe Vesuviano from Alexandroupoli
San Giuseppe Vesuviano is located in Napoli, Italy within 40° 49' 59.88" N 14° 30' 0" E (40.8333, 14.5000) coordinates. The local time in San Giuseppe Vesuviano is 01:09 (09.11.2025)
Alexandroupoli is located in Evros, Greece within 40° 51' 0" N 25° 52' 0.12" E (40.8500, 25.8667) coordinates. The local time in Alexandroupoli is 02:09 (09.11.2025)
The calculated flying distance from Alexandroupoli to Alexandroupoli is 593.73 miles which is equal to 955.51 km.
San Giuseppe Vesuviano, Napoli, Italy