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      Distance from San Fernando to Chateauneuf-les-Martigues

      The shortest distance (air line) between San Fernando and Chateauneuf-les-Martigues is 767.53 mi (1,235.21 km).

      How far is San Fernando from Chateauneuf-les-Martigues

      San Fernando is located in Cádiz, Spain within 36° 28' 0.12" N -7° 47' 60" W (36.4667, -6.2000) coordinates. The local time in San Fernando is 15:08 (19.07.2025)

      Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 15:08 (19.07.2025)

      The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 767.53 miles which is equal to 1,235.21 km.

      San Fernando, Cádiz, Spain

      Related Distances from San Fernando

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      Chateauneuf-les-Martigues, Bouches-du-Rhône, France

      Related Distances to Chateauneuf-les-Martigues