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      Distance from San Clemente to Chateauneuf-les-Martigues

      The shortest distance (air line) between San Clemente and Chateauneuf-les-Martigues is 6,019.01 mi (9,686.66 km).

      How far is San Clemente from Chateauneuf-les-Martigues

      San Clemente is located in California, United States within 33° 26' 59.64" N -118° 23' 23.28" W (33.4499, -117.6102) coordinates. The local time in San Clemente is 06:22 (08.08.2025)

      Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 15:22 (08.08.2025)

      The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 6,019.01 miles which is equal to 9,686.66 km.

      San Clemente, California, United States

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      Chateauneuf-les-Martigues, Bouches-du-Rhône, France

      Related Distances to Chateauneuf-les-Martigues