Distance from San Cataldo to Aleksandrow Lodzki
The shortest distance (air line) between San Cataldo and Aleksandrow Lodzki is 1,023.77 mi (1,647.60 km).
How far is San Cataldo from Aleksandrow Lodzki
San Cataldo is located in Caltanissetta, Italy within 37° 28' 59.88" N 13° 58' 59.88" E (37.4833, 13.9833) coordinates. The local time in San Cataldo is 23:34 (16.11.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 23:34 (16.11.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 1,023.77 miles which is equal to 1,647.60 km.
San Cataldo, Caltanissetta, Italy
Related Distances from San Cataldo
Aleksandrow Lodzki, Łódzki, Poland