Distance from San Angelo to Saint-Avertin
The shortest distance (air line) between San Angelo and Saint-Avertin is 5,128.86 mi (8,254.10 km).
How far is San Angelo from Saint-Avertin
San Angelo is located in Texas, United States within 31° 26' 32.64" N -101° 32' 58.56" W (31.4424, -100.4504) coordinates. The local time in San Angelo is 16:27 (03.09.2025)
Saint-Avertin is located in Indre-et-Loire, France within 47° 22' 0.12" N 0° 43' 36.12" E (47.3667, 0.7267) coordinates. The local time in Saint-Avertin is 23:27 (03.09.2025)
The calculated flying distance from Saint-Avertin to Saint-Avertin is 5,128.86 miles which is equal to 8,254.10 km.
San Angelo, Texas, United States
Related Distances from San Angelo
Saint-Avertin, Indre-et-Loire, France