Distance from Saks to Aleksandrow Lodzki
The shortest distance (air line) between Saks and Aleksandrow Lodzki is 5,004.59 mi (8,054.12 km).
How far is Saks from Aleksandrow Lodzki
Saks is located in Alabama, United States within 33° 42' 42.48" N -86° 8' 47.04" W (33.7118, -85.8536) coordinates. The local time in Saks is 17:58 (21.12.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 00:58 (22.12.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 5,004.59 miles which is equal to 8,054.12 km.
Related Distances from Saks
Aleksandrow Lodzki, Łódzki, Poland