Distance from Saks to Aleksandrow Kujawski
The shortest distance (air line) between Saks and Aleksandrow Kujawski is 4,943.81 mi (7,956.29 km).
How far is Saks from Aleksandrow Kujawski
Saks is located in Alabama, United States within 33° 42' 42.48" N -86° 8' 47.04" W (33.7118, -85.8536) coordinates. The local time in Saks is 02:54 (22.12.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 09:54 (22.12.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,943.81 miles which is equal to 7,956.29 km.
Related Distances from Saks
Aleksandrow Kujawski, Włocławski, Poland