Distance from Saint-Pol-sur-Mer to Cesky Tesin
The shortest distance (air line) between Saint-Pol-sur-Mer and Cesky Tesin is 721.24 mi (1,160.72 km).
How far is Saint-Pol-sur-Mer from Cesky Tesin
Saint-Pol-sur-Mer is located in Nord, France within 51° 1' 53.04" N 2° 20' 38.04" E (51.0314, 2.3439) coordinates. The local time in Saint-Pol-sur-Mer is 23:14 (20.05.2025)
Cesky Tesin is located in Moravskoslezský kraj, Czechia within 49° 44' 45.96" N 18° 37' 33.96" E (49.7461, 18.6261) coordinates. The local time in Cesky Tesin is 23:14 (20.05.2025)
The calculated flying distance from Cesky Tesin to Cesky Tesin is 721.24 miles which is equal to 1,160.72 km.
Saint-Pol-sur-Mer, Nord, France
Related Distances from Saint-Pol-sur-Mer
Cesky Tesin, Moravskoslezský kraj, Czechia