Distance from Saco to Aleksandrow Lodzki
The shortest distance (air line) between Saco and Aleksandrow Lodzki is 3,944.60 mi (6,348.22 km).
How far is Saco from Aleksandrow Lodzki
Saco is located in Maine, United States within 43° 32' 20.4" N -71° 32' 15.36" W (43.5390, -70.4624) coordinates. The local time in Saco is 18:05 (07.11.2025)
Aleksandrow Lodzki is located in Łódzki, Poland within 51° 49' 9.84" N 19° 18' 14.04" E (51.8194, 19.3039) coordinates. The local time in Aleksandrow Lodzki is 00:05 (08.11.2025)
The calculated flying distance from Aleksandrow Lodzki to Aleksandrow Lodzki is 3,944.60 miles which is equal to 6,348.22 km.
Related Distances from Saco
Aleksandrow Lodzki, Łódzki, Poland