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      Distance from Ruskin to Sint-Pieters-Leeuw

      The shortest distance (air line) between Ruskin and Sint-Pieters-Leeuw is 4,620.67 mi (7,436.25 km).

      How far is Ruskin from Sint-Pieters-Leeuw

      Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 23:02 (02.08.2025)

      Sint-Pieters-Leeuw is located in Arr. Halle-Vilvoorde, Belgium within 50° 46' 59.88" N 4° 15' 0" E (50.7833, 4.2500) coordinates. The local time in Sint-Pieters-Leeuw is 05:02 (03.08.2025)

      The calculated flying distance from Sint-Pieters-Leeuw to Sint-Pieters-Leeuw is 4,620.67 miles which is equal to 7,436.25 km.

      Ruskin, Florida, United States

      Related Distances from Ruskin

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      Sint-Pieters-Leeuw, Arr. Halle-Vilvoorde, Belgium

      Related Distances to Sint-Pieters-Leeuw