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      Distance from Ruskin to Sint-Katelijne-Waver

      The shortest distance (air line) between Ruskin and Sint-Katelijne-Waver is 4,627.10 mi (7,446.60 km).

      How far is Ruskin from Sint-Katelijne-Waver

      Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 15:08 (01.08.2025)

      Sint-Katelijne-Waver is located in Arr. Mechelen, Belgium within 51° 4' 0.12" N 4° 31' 59.88" E (51.0667, 4.5333) coordinates. The local time in Sint-Katelijne-Waver is 21:08 (01.08.2025)

      The calculated flying distance from Sint-Katelijne-Waver to Sint-Katelijne-Waver is 4,627.10 miles which is equal to 7,446.60 km.

      Ruskin, Florida, United States

      Related Distances from Ruskin

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      Sint-Katelijne-Waver, Arr. Mechelen, Belgium

      Related Distances to Sint-Katelijne-Waver