Distance from Ruskin to Hoogstraten
The shortest distance (air line) between Ruskin and Hoogstraten is 4,630.40 mi (7,451.91 km).
How far is Ruskin from Hoogstraten
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 02:13 (30.07.2025)
Hoogstraten is located in Arr. Turnhout, Belgium within 51° 23' 60" N 4° 46' 0.12" E (51.4000, 4.7667) coordinates. The local time in Hoogstraten is 08:13 (30.07.2025)
The calculated flying distance from Hoogstraten to Hoogstraten is 4,630.40 miles which is equal to 7,451.91 km.
Ruskin, Florida, United States
Related Distances from Ruskin
Hoogstraten, Arr. Turnhout, Belgium