Distance from Ruskin to Begijnendijk
The shortest distance (air line) between Ruskin and Begijnendijk is 4,638.53 mi (7,464.99 km).
How far is Ruskin from Begijnendijk
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 22:00 (28.07.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 04:00 (29.07.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 4,638.53 miles which is equal to 7,464.99 km.
Ruskin, Florida, United States
Related Distances from Ruskin
Begijnendijk, Arr. Leuven, Belgium