Distance from Ruskin to Bad Sassendorf
The shortest distance (air line) between Ruskin and Bad Sassendorf is 4,766.26 mi (7,670.56 km).
How far is Ruskin from Bad Sassendorf
Ruskin is located in Florida, United States within 27° 42' 23.4" N -83° 34' 44.76" W (27.7065, -82.4209) coordinates. The local time in Ruskin is 08:48 (03.09.2025)
Bad Sassendorf is located in Soest, Germany within 51° 34' 59.16" N 8° 10' 0.12" E (51.5831, 8.1667) coordinates. The local time in Bad Sassendorf is 14:48 (03.09.2025)
The calculated flying distance from Bad Sassendorf to Bad Sassendorf is 4,766.26 miles which is equal to 7,670.56 km.
Ruskin, Florida, United States
Related Distances from Ruskin
Bad Sassendorf, Soest, Germany