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      Distance from Rosiori de Vede to Chateauneuf-les-Martigues

      The shortest distance (air line) between Rosiori de Vede and Chateauneuf-les-Martigues is 988.65 mi (1,591.08 km).

      How far is Rosiori de Vede from Chateauneuf-les-Martigues

      Rosiori de Vede is located in Teleorman, Romania within 44° 6' 41.04" N 24° 59' 39.12" E (44.1114, 24.9942) coordinates. The local time in Rosiori de Vede is 11:54 (27.11.2025)

      Chateauneuf-les-Martigues is located in Bouches-du-Rhône, France within 43° 22' 59.16" N 5° 9' 51.12" E (43.3831, 5.1642) coordinates. The local time in Chateauneuf-les-Martigues is 10:54 (27.11.2025)

      The calculated flying distance from Chateauneuf-les-Martigues to Chateauneuf-les-Martigues is 988.65 miles which is equal to 1,591.08 km.

      Rosiori de Vede, Teleorman, Romania

      Related Distances from Rosiori de Vede

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      Rosiori de Vede to Pitesti52.14 mi (83.91 km)
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      Rosiori de Vede to Ramnicu Valcea75.07 mi (120.82 km)
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      Rosiori de Vede to Braila166.07 mi (267.27 km)
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      Rosiori de Vede to Suceava251.99 mi (405.54 km)
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      Chateauneuf-les-Martigues, Bouches-du-Rhône, France

      Related Distances to Chateauneuf-les-Martigues