Distance from Roscoe to Aleksandrow Kujawski
The shortest distance (air line) between Roscoe and Aleksandrow Kujawski is 4,578.72 mi (7,368.74 km).
How far is Roscoe from Aleksandrow Kujawski
Roscoe is located in Illinois, United States within 42° 25' 32.16" N -90° 59' 29.76" W (42.4256, -89.0084) coordinates. The local time in Roscoe is 09:16 (11.11.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 16:16 (11.11.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,578.72 miles which is equal to 7,368.74 km.
Roscoe, Illinois, United States
Related Distances from Roscoe
Aleksandrow Kujawski, Włocławski, Poland