Distance from Roosevelt to Diepenbeek
The shortest distance (air line) between Roosevelt and Diepenbeek is 3,685.08 mi (5,930.56 km).
How far is Roosevelt from Diepenbeek
Roosevelt is located in New York, United States within 40° 40' 46.92" N -74° 24' 58.68" W (40.6797, -73.5837) coordinates. The local time in Roosevelt is 12:30 (29.07.2025)
Diepenbeek is located in Arr. Hasselt, Belgium within 50° 54' 25.92" N 5° 25' 3" E (50.9072, 5.4175) coordinates. The local time in Diepenbeek is 18:30 (29.07.2025)
The calculated flying distance from Diepenbeek to Diepenbeek is 3,685.08 miles which is equal to 5,930.56 km.
Roosevelt, New York, United States
Related Distances from Roosevelt
Diepenbeek, Arr. Hasselt, Belgium