Distance from Robbinsdale to Cristuru Secuiesc
The shortest distance (air line) between Robbinsdale and Cristuru Secuiesc is 5,097.70 mi (8,203.95 km).
How far is Robbinsdale from Cristuru Secuiesc
Robbinsdale is located in Minnesota, United States within 45° 1' 33.96" N -94° 40' 0.48" W (45.0261, -93.3332) coordinates. The local time in Robbinsdale is 01:43 (17.11.2025)
Cristuru Secuiesc is located in Harghita, Romania within 46° 17' 30.12" N 25° 2' 7.08" E (46.2917, 25.0353) coordinates. The local time in Cristuru Secuiesc is 09:43 (17.11.2025)
The calculated flying distance from Cristuru Secuiesc to Cristuru Secuiesc is 5,097.70 miles which is equal to 8,203.95 km.
Robbinsdale, Minnesota, United States
Related Distances from Robbinsdale
Cristuru Secuiesc, Harghita, Romania