Distance from Robbinsdale to Aleksandrow Kujawski
The shortest distance (air line) between Robbinsdale and Aleksandrow Kujawski is 4,571.66 mi (7,357.38 km).
How far is Robbinsdale from Aleksandrow Kujawski
Robbinsdale is located in Minnesota, United States within 45° 1' 33.96" N -94° 40' 0.48" W (45.0261, -93.3332) coordinates. The local time in Robbinsdale is 08:17 (12.11.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 15:17 (12.11.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,571.66 miles which is equal to 7,357.38 km.
Robbinsdale, Minnesota, United States
Related Distances from Robbinsdale
Aleksandrow Kujawski, Włocławski, Poland