Distance from Roanoke to Sajoszentpeter
The shortest distance (air line) between Roanoke and Sajoszentpeter is 4,788.38 mi (7,706.16 km).
How far is Roanoke from Sajoszentpeter
Roanoke is located in Virginia, United States within 37° 16' 42.6" N -80° 2' 30.84" W (37.2785, -79.9581) coordinates. The local time in Roanoke is 15:54 (23.10.2025)
Sajoszentpeter is located in Borsod-Abaúj-Zemplén, Hungary within 48° 13' 0.84" N 20° 43' 5.88" E (48.2169, 20.7183) coordinates. The local time in Sajoszentpeter is 21:54 (23.10.2025)
The calculated flying distance from Sajoszentpeter to Sajoszentpeter is 4,788.38 miles which is equal to 7,706.16 km.
Roanoke, Virginia, United States
Related Distances from Roanoke
Sajoszentpeter, Borsod-Abaúj-Zemplén, Hungary