Distance from Reynoldsburg to Steenokkerzeel
The shortest distance (air line) between Reynoldsburg and Steenokkerzeel is 4,047.61 mi (6,514.01 km).
How far is Reynoldsburg from Steenokkerzeel
Reynoldsburg is located in Ohio, United States within 39° 57' 31.68" N -83° 12' 20.52" W (39.9588, -82.7943) coordinates. The local time in Reynoldsburg is 16:02 (08.10.2025)
Steenokkerzeel is located in Arr. Halle-Vilvoorde, Belgium within 50° 55' 8.04" N 4° 30' 29.88" E (50.9189, 4.5083) coordinates. The local time in Steenokkerzeel is 22:02 (08.10.2025)
The calculated flying distance from Steenokkerzeel to Steenokkerzeel is 4,047.61 miles which is equal to 6,514.01 km.
Reynoldsburg, Ohio, United States
Related Distances from Reynoldsburg
Steenokkerzeel, Arr. Halle-Vilvoorde, Belgium