Distance from Reynoldsburg to Scherpenheuvel
The shortest distance (air line) between Reynoldsburg and Scherpenheuvel is 4,062.93 mi (6,538.65 km).
How far is Reynoldsburg from Scherpenheuvel
Reynoldsburg is located in Ohio, United States within 39° 57' 31.68" N -83° 12' 20.52" W (39.9588, -82.7943) coordinates. The local time in Reynoldsburg is 15:13 (06.08.2025)
Scherpenheuvel is located in Arr. Leuven, Belgium within 51° 0' 37.08" N 4° 58' 22.08" E (51.0103, 4.9728) coordinates. The local time in Scherpenheuvel is 21:13 (06.08.2025)
The calculated flying distance from Scherpenheuvel to Scherpenheuvel is 4,062.93 miles which is equal to 6,538.65 km.
Reynoldsburg, Ohio, United States
Related Distances from Reynoldsburg
Scherpenheuvel, Arr. Leuven, Belgium