Distance from Reeuwijk to Aleksandrow Kujawski
The shortest distance (air line) between Reeuwijk and Aleksandrow Kujawski is 589.64 mi (948.94 km).
How far is Reeuwijk from Aleksandrow Kujawski
Reeuwijk is located in Oost-Zuid-Holland, Netherlands within 52° 2' 60" N 4° 43' 48" E (52.0500, 4.7300) coordinates. The local time in Reeuwijk is 17:32 (13.11.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 17:32 (13.11.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 589.64 miles which is equal to 948.94 km.
Reeuwijk, Oost-Zuid-Holland, Netherlands
Related Distances from Reeuwijk
Aleksandrow Kujawski, Włocławski, Poland