Distance from Radzyn Podlaski to Florida Ridge
The shortest distance (air line) between Radzyn Podlaski and Florida Ridge is 5,257.60 mi (8,461.28 km).
How far is Radzyn Podlaski from Florida Ridge
Radzyn Podlaski is located in Bialski, Poland within 51° 46' 58.08" N 22° 37' 27.12" E (51.7828, 22.6242) coordinates. The local time in Radzyn Podlaski is 21:01 (05.09.2025)
Florida Ridge is located in Florida, United States within 27° 34' 49.8" N -81° 36' 54.72" W (27.5805, -80.3848) coordinates. The local time in Florida Ridge is 15:01 (05.09.2025)
The calculated flying distance from Florida Ridge to Florida Ridge is 5,257.60 miles which is equal to 8,461.28 km.
Radzyn Podlaski, Bialski, Poland
Related Distances from Radzyn Podlaski
Florida Ridge, Florida, United States