Distance from Radzyn Podlaski to Felixstowe
The shortest distance (air line) between Radzyn Podlaski and Felixstowe is 904.30 mi (1,455.34 km).
How far is Radzyn Podlaski from Felixstowe
Radzyn Podlaski is located in Bialski, Poland within 51° 46' 58.08" N 22° 37' 27.12" E (51.7828, 22.6242) coordinates. The local time in Radzyn Podlaski is 23:44 (20.08.2025)
Felixstowe is located in Suffolk, United Kingdom within 51° 57' 50.04" N 1° 21' 5.4" E (51.9639, 1.3515) coordinates. The local time in Felixstowe is 22:44 (20.08.2025)
The calculated flying distance from Felixstowe to Felixstowe is 904.30 miles which is equal to 1,455.34 km.
Radzyn Podlaski, Bialski, Poland
Related Distances from Radzyn Podlaski
Felixstowe, Suffolk, United Kingdom