Distance from Prospect Heights to Sassenberg
The shortest distance (air line) between Prospect Heights and Sassenberg is 4,232.96 mi (6,812.28 km).
How far is Prospect Heights from Sassenberg
Prospect Heights is located in Illinois, United States within 42° 6' 14.04" N -88° 4' 23.88" W (42.1039, -87.9267) coordinates. The local time in Prospect Heights is 06:32 (20.08.2025)
Sassenberg is located in Warendorf, Germany within 51° 59' 22.92" N 8° 2' 26.88" E (51.9897, 8.0408) coordinates. The local time in Sassenberg is 13:32 (20.08.2025)
The calculated flying distance from Sassenberg to Sassenberg is 4,232.96 miles which is equal to 6,812.28 km.
Prospect Heights, Illinois, United States
Related Distances from Prospect Heights
Sassenberg, Warendorf, Germany