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      Distance from Prospect Heights to San Baudilio de Llobregat

      The shortest distance (air line) between Prospect Heights and San Baudilio de Llobregat is 4,400.56 mi (7,082.02 km).

      How far is Prospect Heights from San Baudilio de Llobregat

      Prospect Heights is located in Illinois, United States within 42° 6' 14.04" N -88° 4' 23.88" W (42.1039, -87.9267) coordinates. The local time in Prospect Heights is 08:19 (14.11.2025)

      San Baudilio de Llobregat is located in Barcelona, Spain within 41° 20' 44.88" N 2° 2' 30.12" E (41.3458, 2.0417) coordinates. The local time in San Baudilio de Llobregat is 15:19 (14.11.2025)

      The calculated flying distance from San Baudilio de Llobregat to San Baudilio de Llobregat is 4,400.56 miles which is equal to 7,082.02 km.

      Prospect Heights, Illinois, United States

      Related Distances from Prospect Heights

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      Prospect Heights to San Francisco (California)1,840.57 mi (2,962.11 km)
      Prospect Heights to Chicago (Illinois)22.16 mi (35.66 km)
      Prospect Heights to Detroit (Michigan)247.48 mi (398.28 km)
      Prospect Heights to St. Louis (Missouri)268.88 mi (432.72 km)
      Prospect Heights to Minneapolis (Minnesota)332.47 mi (535.05 km)
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      San Baudilio de Llobregat, Barcelona, Spain

      Related Distances to San Baudilio de Llobregat