Distance from Prospect Heights to Albany
The shortest distance (air line) between Prospect Heights and Albany is 721.22 mi (1,160.69 km).
How far is Prospect Heights from Albany
Prospect Heights is located in Illinois, United States within 42° 6' 14.04" N -88° 4' 23.88" W (42.1039, -87.9267) coordinates. The local time in Prospect Heights is 07:41 (21.12.2025)
Albany is located in New York, United States within 42° 39' 59.04" N -74° 12' 4.68" W (42.6664, -73.7987) coordinates. The local time in Albany is 08:41 (21.12.2025)
The calculated flying distance from Albany to Albany is 721.22 miles which is equal to 1,160.69 km.
Prospect Heights, Illinois, United States
Related Distances from Prospect Heights
Albany, New York, United States