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      Distance from Preakness to Villanueva de la Canada

      The shortest distance (air line) between Preakness and Villanueva de la Canada is 3,573.78 mi (5,751.45 km).

      How far is Preakness from Villanueva de la Canada

      Preakness is located in New Jersey, United States within 40° 56' 17.52" N -75° 46' 32.88" W (40.9382, -74.2242) coordinates. The local time in Preakness is 01:12 (17.11.2025)

      Villanueva de la Canada is located in Madrid, Spain within 40° 27' 0" N -4° 1' 0.12" W (40.4500, -3.9833) coordinates. The local time in Villanueva de la Canada is 07:12 (17.11.2025)

      The calculated flying distance from Villanueva de la Canada to Villanueva de la Canada is 3,573.78 miles which is equal to 5,751.45 km.

      Preakness, New Jersey, United States

      Related Distances from Preakness

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      Preakness to New York (New York)23.00 mi (37.01 km)
      Preakness to Brooklyn (New York)24.55 mi (39.50 km)
      Preakness to Boston (Massachusetts)188.08 mi (302.68 km)
      Preakness to Washington (District of Columbia)204.01 mi (328.33 km)
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      Villanueva de la Canada, Madrid, Spain

      Related Distances to Villanueva de la Canada