Distance from Potomac to Aleksandrow Kujawski
The shortest distance (air line) between Potomac and Aleksandrow Kujawski is 4,353.60 mi (7,006.44 km).
How far is Potomac from Aleksandrow Kujawski
Potomac is located in Maryland, United States within 39° 0' 50.76" N -78° 48' 20.52" W (39.0141, -77.1943) coordinates. The local time in Potomac is 03:27 (10.11.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 09:27 (10.11.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 4,353.60 miles which is equal to 7,006.44 km.
Potomac, Maryland, United States
Related Distances from Potomac
Aleksandrow Kujawski, Włocławski, Poland