Distance from Port Arthur to Aleksandrow Kujawski
The shortest distance (air line) between Port Arthur and Aleksandrow Kujawski is 5,439.03 mi (8,753.27 km).
How far is Port Arthur from Aleksandrow Kujawski
Port Arthur is located in Texas, United States within 29° 51' 19.44" N -94° 4' 24.96" W (29.8554, -93.9264) coordinates. The local time in Port Arthur is 08:26 (08.11.2025)
Aleksandrow Kujawski is located in Włocławski, Poland within 52° 52' 36.12" N 18° 41' 36.96" E (52.8767, 18.6936) coordinates. The local time in Aleksandrow Kujawski is 15:26 (08.11.2025)
The calculated flying distance from Aleksandrow Kujawski to Aleksandrow Kujawski is 5,439.03 miles which is equal to 8,753.27 km.
Port Arthur, Texas, United States
Related Distances from Port Arthur
Aleksandrow Kujawski, Włocławski, Poland