Distance from Phillipsburg to Begijnendijk
The shortest distance (air line) between Phillipsburg and Begijnendijk is 3,720.69 mi (5,987.87 km).
How far is Phillipsburg from Begijnendijk
Phillipsburg is located in New Jersey, United States within 40° 41' 21.84" N -76° 49' 4.44" W (40.6894, -75.1821) coordinates. The local time in Phillipsburg is 19:38 (29.07.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 01:38 (30.07.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,720.69 miles which is equal to 5,987.87 km.
Phillipsburg, New Jersey, United States
Related Distances from Phillipsburg
Begijnendijk, Arr. Leuven, Belgium