Distance from Peekskill to Sveti Jurij
The shortest distance (air line) between Peekskill and Sveti Jurij is 4,237.81 mi (6,820.10 km).
How far is Peekskill from Sveti Jurij
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 10:07 (13.11.2025)
Sveti Jurij is located in Pomurska, Slovenia within 46° 34' 5.88" N 16° 1' 13.08" E (46.5683, 16.0203) coordinates. The local time in Sveti Jurij is 16:07 (13.11.2025)
The calculated flying distance from Sveti Jurij to Sveti Jurij is 4,237.81 miles which is equal to 6,820.10 km.
Peekskill, New York, United States
Related Distances from Peekskill
Sveti Jurij, Pomurska, Slovenia