Distance from Peekskill to Romanshorn
The shortest distance (air line) between Peekskill and Romanshorn is 3,930.36 mi (6,325.30 km).
How far is Peekskill from Romanshorn
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 05:45 (17.11.2025)
Romanshorn is located in Thurgau, Switzerland within 47° 33' 48.6" N 9° 21' 23.04" E (47.5635, 9.3564) coordinates. The local time in Romanshorn is 11:45 (17.11.2025)
The calculated flying distance from Romanshorn to Romanshorn is 3,930.36 miles which is equal to 6,325.30 km.
Peekskill, New York, United States
Related Distances from Peekskill
Romanshorn, Thurgau, Switzerland