Distance from Peekskill to Panevezys
The shortest distance (air line) between Peekskill and Panevezys is 4,216.35 mi (6,785.56 km).
How far is Peekskill from Panevezys
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 06:15 (26.08.2025)
Panevezys is located in Panevėžio apskritis, Lithuania within 55° 43' 59.88" N 24° 21' 0" E (55.7333, 24.3500) coordinates. The local time in Panevezys is 13:15 (26.08.2025)
The calculated flying distance from Panevezys to Panevezys is 4,216.35 miles which is equal to 6,785.56 km.
Peekskill, New York, United States
Related Distances from Peekskill
Panevezys, Panevėžio apskritis, Lithuania