Distance from Peekskill to Janow Lubelski
The shortest distance (air line) between Peekskill and Janow Lubelski is 4,334.11 mi (6,975.08 km).
How far is Peekskill from Janow Lubelski
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 18:42 (29.08.2025)
Janow Lubelski is located in Puławski, Poland within 50° 43' 0.12" N 22° 25' 0.12" E (50.7167, 22.4167) coordinates. The local time in Janow Lubelski is 00:42 (30.08.2025)
The calculated flying distance from Janow Lubelski to Janow Lubelski is 4,334.11 miles which is equal to 6,975.08 km.
Peekskill, New York, United States
Related Distances from Peekskill
Janow Lubelski, Puławski, Poland