Distance from Peekskill to Begijnendijk
The shortest distance (air line) between Peekskill and Begijnendijk is 3,643.69 mi (5,863.95 km).
How far is Peekskill from Begijnendijk
Peekskill is located in New York, United States within 41° 17' 18.24" N -74° 4' 38.28" W (41.2884, -73.9227) coordinates. The local time in Peekskill is 01:42 (29.07.2025)
Begijnendijk is located in Arr. Leuven, Belgium within 51° 1' 6.96" N 4° 47' 6" E (51.0186, 4.7850) coordinates. The local time in Begijnendijk is 07:42 (29.07.2025)
The calculated flying distance from Begijnendijk to Begijnendijk is 3,643.69 miles which is equal to 5,863.95 km.
Peekskill, New York, United States
Related Distances from Peekskill
Begijnendijk, Arr. Leuven, Belgium