Distance from Pawtucket to Ozarow Mazowiecki
The shortest distance (air line) between Pawtucket and Ozarow Mazowiecki is 4,098.63 mi (6,596.11 km).
How far is Pawtucket from Ozarow Mazowiecki
Pawtucket is located in Rhode Island, United States within 41° 52' 27.84" N -72° 37' 32.52" W (41.8744, -71.3743) coordinates. The local time in Pawtucket is 09:33 (05.09.2025)
Ozarow Mazowiecki is located in Warszawski zachodni, Poland within 52° 13' 0.12" N 20° 48' 0" E (52.2167, 20.8000) coordinates. The local time in Ozarow Mazowiecki is 15:33 (05.09.2025)
The calculated flying distance from Ozarow Mazowiecki to Ozarow Mazowiecki is 4,098.63 miles which is equal to 6,596.11 km.
Pawtucket, Rhode Island, United States
Related Distances from Pawtucket
Ozarow Mazowiecki, Warszawski zachodni, Poland